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Subject: Re: [xsl] String contains a regex and then junk ... how to remove the junk? From: "Norm Tovey-Walsh ndw@xxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Mon, 16 Dec 2024 13:43:04 -0000 |
> I wrote a recursive function to do this. See below. Is there is a simpler
way to do it?
If the regex is always in parens, and if the junk that follows never contains
a b)b, then just look for the last b)b.
If the regex is always in parens, but the junk might include b(b and/or
b)b then itbs going to be harder.
If the regex isnbt always in parens, b& Ibm not sure the problem is
tractable. A string of the form babcdb could be interpreted several ways
depending on whether bbcdb, bcdb, bdb, or bb is considered
junk.
On a quick skim, I wasnbt able to persuade myself that your recursive
solution was handling escaped parens, if thatbs an issue
Assuming the regex is always in parens, I cooked up this ixml grammar in a
moment or two, but it doesnbt handle escaped parens either.
text = regex, junk? .
regex = '(', inner*, ')' .
-inner = -regex | ~["()"] .
junk = ~[]* .
Be seeing you,
norm
--
Norm Tovey-Walsh <ndw@xxxxxxxxxx>
https://norm.tovey-walsh.com/
> Weeks of programming can save you hours of planning.
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