Subject: Re: [xsl] Replace the portion of text that matches pattern: XPath versus SNOBOL From: "Martin Honnen martin.honnen@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Sat, 22 Mar 2025 13:00:01 -0000 |
Suppose that you want to only replace the first match, i.e., we want
"BELANCE." I do not think that there is any way to configure the XPath replace() function to "Replace only the first match." Please correct me if I am wrong about this.
In functx it is implemented: https://www.datypic.com/xsl/functx_replace-first.html
<xsl:function name="functx:replace-first" as="xs:string" B B B B B B B B B B B B B xmlns:functx="http://www.functx.com"> B <xsl:param name="arg" as="xs:string?"/> B <xsl:param name="pattern" as="xs:string"/> B <xsl:param name="replacement" as="xs:string"/>
B <xsl:sequence select=" B B replace($arg, concat('(^.*?)', $pattern), B B B B B B B B B B B B concat('$1',$replacement)) B "/>
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