Re: [xsl] Running a stylesheet with Python

["Martin Honnen martin.honnen@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

On 27/08/2025 18:24, dvint@xxxxxxxxx wrote:
> So this looks absolute to me, here is the definition
>
> B B B B <xsl:param name="srcPath"
> B B B B B B B  select="substring-before(base-uri(.), tokenize(base-uri(.),
> '/')[last()])"/>
>
> B B B B <xsl:variable name="MODULES_LOC" >
> B B B B B B B  <xsl:choose>
> B B B B B B B B B B B  <xsl:when test="$MODE='p1'">
> B B B B B B B B B B B B B B B 
<xsl:text>../../../../asciidoc/modules/</xsl:text>
> B B B B B B B B B B B  </xsl:when>
> B B B B B B B B B B B  <xsl:otherwise>
> B B B B B B B B B B B B B B B  <xsl:text>../asciidoc/modules/</xsl:text>
> B B B B B B B B B B B  </xsl:otherwise>
> B B B B B B B  </xsl:choose>
> B B B B </xsl:variable>
>
> B B B B <xsl:variable name="PARTIALS"
> select="substring-after(concat($srcPath, $MODULES_LOC,
> 'ROOT/partials/'), 'file:')"/>
>
> It is based upon the input XML file and then adds a relative path from
> there.


I don't think PARTIALS contains an absolute file: URI if you explicitly
strip the `file:` part of the URI with substring-after. An absolute
file: URI starts with `file:`, so don't strip that.