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Re: [xsl] the count function

Subject: Re: [xsl] the count function
From: "John Lumley john.lumley@xxxxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Date: Fri, 2 Oct 2026 15:10:08 -0000
The reason is that the borb operator isnbt exactly what you think it
might be, in this specific context. borb is a Boolean borb, not a set
union. In XSLT2 the set union operator over nodes is b|b, which removes
duplicates (that is the same node referenced more than once.

So you need count(ancestor::li | ancestor::step)

John Lumley
john@xxxxxxxxxxxxxx

> On 2 Oct 2026, at 16:04, Trevor Nicholls trevor@xxxxxxxxxxxxxxxxxx
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:
>
> ancestor::li or ancestor::step
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