|
Subject: Re: Mixed content transformation From: Keith Visco <kvisco@xxxxxxxxx> Date: Thu, 14 Jan 1999 10:07:40 -0500 |
Paul,
Here is one solution:
<xsl:template match="foo">
<P><xsl:apply-templates/></P>
</xsl:template>
<xsl:template match="bar">
<B><xsl:apply-templates/></B>
</xsl:template>
you could also use:
<xsl:template match="foo">
<P>
<xsl:for-each select="bar">
<B><xsl:apply-templates/></B>
</xsl:for-each>
</P>
</xsl:template>
Paul_Tihansky@xxxxxxxxxxxx wrote:
>
> I have a simple question, but I couldn't find any references to it in
> the XSL working draft. How can I transform mixed content using XSL? I
> think I remember hearing that Microsoft can't handle it at this point, but
> I didn't even see it covered in the working draft.
>
> For example, lets say I have this simple XML snippet:
> <foo>This is <bar>mixed</bar> content.</foo>
>
> What would my XSL look like to transform this to:
> <P>This is <B>mixed</B> content.</P>
>
> Am I missing something obvious?
>
> Thanks a bunch,
> Paul
>
> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
| Current Thread |
|---|
|
| <- Previous | Index | Next -> |
|---|---|---|
| Mixed content transformation, Paul_Tihansky | Thread | Re: Mixed content transformation, Guy_Murphy |
| Re: GOTCHA!, Oren Ben-Kiki | Date | Re: Mixed content transformation, Guy_Murphy |
| Month |