Subject: RE: Union and descendants: count(.//name1|name2) ? Doesn't perfor m Union? From: Kay Michael <Michael.Kay@xxxxxxx> Date: Tue, 13 Jul 1999 09:52:22 +0100 |
> > count(.//entry|e) > > Returns only the number of "entry" elements without adding > the number of e matches to the result. This parses as count( (.//entry) | (e) ) and should return the sum of the number of descendant "entry" elements and the number of child "e" elements. If you want to include descendant "e" elements, write count(.//entry | .//e) or (probably more efficient, because a union involves elimination of duplicates, which is not actually needed here) count(.//entry) + count(.//e) > > count(./e|entry) > > Works fine, counting both It will, because this expression is equivalent to count((./e) | (./entry)) Mike Kay XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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