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Subject: Re: n squared behavior with XT for 'preceding' tests? From: "Sebastian Rahtz" <sebastian.rahtz@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx> Date: Wed, 21 Jul 1999 23:40:59 +0100 (BST) |
If I understand David Carlisle's code aright, he explicitly processes
the first <hd> element:
<xsl:template match="test">
<xsl:apply-templates select="hd[1]"/>
</xsl:template>
and then processes the following identical ones:
<xsl:apply-templates mode="later"
select="from-following-siblings(hd[text()=$x])"/>
followed by the next non-identical one
<xsl:apply-templates
select="from-following-siblings(hd[not(text()=$x)][1])"/>
Two questions:
1. why doesn't the the second stage
(select="from-following-siblings(hd[text()=$x])"/>)
skip over the non-identical siblings? so if I have
<hd>Foo</hd>
<hd>Bar</hd>
<hd>Foo</dd>
doesn't the "Foo" one pick up the #3 "Foo" and then the #2 "Bar"?
they are all "following-siblings", and the select isn't a _while
test is true_, but a _select all that match_ test, no?
or did the original spec say that the things were pre-sorted?
2. I was reading this hoping I could use a similar technique to clean
up some MathML:
<mi>A</mi><mi>v</mi>
which I want as
<mi>Av</mi>
but since this can occur in many places, I don't have the luxury
of the top-level "go process the <x> elements". I could do
"select the text of all the <mi> following-siblings" in the <mi>
template, but then if I have
<mi>A</mi><mi>v</mi><mo>x</mo><mi>A</mi><mi>v</mi>
I run up againt the same problem, that "following <mi> siblings"
will pick up ALL the <mi>s in this sequence, and not stop at the
<mo>
Am I confusing myself, and you, dear reader? Can I simplify
<mi>A</mi><mi>v</mi> in straight XSL?
sebastian
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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