|
Subject: RE: Group By an Element... From: "Earl Bingham" <earl@xxxxxxxxx> Date: Mon, 30 Aug 1999 10:06:03 -0700 |
Your XML data can be queried using the text()
For instance you have the following:
<header>
<category>
Food
</category>
<value>
Bananas
</value>
<category>
</category>
</header>
You could use the following to get the value Bananas:
<xsl:value-of
select="header/value[from-preceding-sibling::node()='Food']/text()"/>
My XML data contains Categories for Items.
I need to print Group By Headers for the Items
using XSLT.
These headers get printed only if the Item being
transformed has a
category different from its previous item.
Is there a way to do this in XSL ?
Thanks
Vandana
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
| Current Thread |
|---|
|
| <- Previous | Index | Next -> |
|---|---|---|
| Group By an Element..., Vandana Deep | Thread | XSLT traverse and Java entension, Honglin Su |
| Re: XSL FO. How To., David Tolpin | Date | Date.xsl - incorrect function refer, Brigitte Fenton |
| Month |