xsl:if confusion

["Sargeant, Richard (GEIS)" <Richard.Sargeant@xxxxxxxxxxx>]

Hi,

   While processing a node I need to do conditional processing based on the
contents of another node of the same parent. For example my XML looks like

   <USER>
      <TYPE>1</TYPE>
      <PASSWORD>pwd</PASSWORD>
   </USER>

 The xsl for node password is

   <xsl:template match="PASSWORD">
      <td>
         <font face="arial" size="2">Password: </font>
         <font face="arial" size="2" color="#000080">
         <xsl:choose>
            <xsl:when test="../TYPE=1">########</xsl:when>
            <xsl:otherwise>
               <xsl:value-of select="."/>
            </xsl:otherwise>
         </xsl:choose>
         </font>
      </td>
   </xsl:template>

I've also tried ../TYPE/text()='1' but that also fails. What I'm I doing
wrong ?

regards
   Richard


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