select-distinct in for-each ?

["Clark C. Evans" <clark.evans@xxxxxxxxxxxxxxxxxxxx>]

Hello.  I have a hierarchy 3 layers deep, and I'm
trying to build a cross-reference of a repeating
group in the lowest layer.  To do this, I have
a <xsl:for-each ... /> with a <xsl:sort ... /> .
As you guess, I have duplicates that need to
be removed -- I'm looking for a select-distinct.
  
I found this in the FAQ but it partially works:
       
    Q: 2.46   
    
    How to remove duplicate nodes from a
    node-set according to content?
    
    A: 2.46 - David Carlisle
     
    select="reference[not(@name=following::reference/@name)]"
    will return you a list of reference elements with no
    two having the same name.
       
Here is my sample data:
  
 <a>
    <b>
      <c>X</c>
    </b>
    <b>
      <c>X</c>
    </b>
    <b>
      <x>Z</x>
    </b>
</a>
<a>
    <b>
      <c>X</c>
    </b>
</a>
       

What I want is:
       
X
Z

What I tried (among many many other things...)
    
<xsl:for-each select="//c[not(text()=following::c/text())]" >
  <xsl:sort order="ascending" select="." />
  <xsl:value-of select="." /><br/>
</xsl:for-each>
       
      
What I get using August 22 version of XT
       
X
X
Z
     
...

It seems that following:: is grabbing the
next sibling, however, if you go up one
node and then go back down it does not
seem to pick this up.

Am I missing anything?

Thanks!
       
Clark
 



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