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Subject: Re: replacing characters in a string From: David Carlisle <davidc@xxxxxxxxx> Date: Fri, 15 Oct 1999 13:33:02 +0100 (BST) |
> see if there's an apostrophe character, if so, convert this
> to \', if not, just output the value of 'name'.
something like this?
David
<xsl:call-template name="string-replace">
<xsl:with-param name="from" select="'''"/>
<xsl:with-param name="to" select="'\''"/>
<xsl:with-param name="string" select="."/>
</xsl:call-template>
<!-- replace all occurences of the character(s) `from'
by the string `to' in the string `string'.-->
<xsl:template name="string-replace" >
<xsl:param name="string"/>
<xsl:param name="from"/>
<xsl:param name="to"/>
<xsl:choose>
<xsl:when test="contains($string,$from)">
<xsl:value-of select="substring-before($string,$from)"/>
<xsl:value-of select="$to"/>
<xsl:call-template name="string-replace">
<xsl:with-param name="string" select="substring-after($string,$from)"/>
<xsl:with-param name="from" select="$from"/>
<xsl:with-param name="to" select="$to"/>
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$string"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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