Re: document(), apply-templates and parameters

["Tangi Vass" <tangivass@xxxxxxxxxxxxxx>]

Scott Boag from Lotus sent me a mail of explanations :

 

"document('foo.xml')" selects the '/' node on foo.xml, which has not template,

so it falls to the default template. Since parameters do not get automatically

passed from template to template, you loose the parameter in the default

template for '/'.  If you do select="document('foo.xml')/*", you will get the

expected results.

Before his help, I found a workaround :

    <xsl:for-each select="document('foo.xml')">
      <xsl:apply-templates>
        <xsl:with-param name="arg1>ok</xsl:with-param>
      </xsl:apply-templates>
    </xsl:for-each>

but without understanding why it works (it doesn't use the default template for '/' ;-)

 

So thanks a lot for your explanations, Scott.

 

Tangi

----- Original Message -----

From: Tangi Vass

To: Mulberrytech's XSL-list

Sent: Wednesday, 20 October, 1999 16:01

Subject: document(), apply-templates and parameters

I tried to do this:

 

    <xsl:apply-templates select="document('foo.xml')">
      <xsl:with-param name="arg1">ok</xsl:with-param>
    </xsl:apply-templates>

 

But it fails: arg1's value is ignored.

 

Could someone tell me why ("normal" feature to prevent potential side-effects, bug in LotusXSL 0.18.2, ...) ?

 

Thanks in advance,

 

Tangi