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Subject: Re: Converting XML <link> to HTML anchor From: "Brett McLaughlin" <bmclaugh@xxxxxxxx> Date: Wed, 8 Dec 1999 22:11:49 -0600 |
> Michael Teigman wrote:
> > I have an xml like this:
> >
> > <text>
> > <p>Text1</p>
> > <p>Text2 <link href="link1">label1</link></p>
> > <p><link href="link2">label2</link></p>
> > <p>Text3 <link href="link3">label3</link> text4 <link
> > href="link4">label4</link> text 5</p>
> > </text>
> >
> > For example I want from the above:
> >
> > <p>
> > <p>Text1</p>
> > <p>Text2 <a href="link1">label1</a></p>
> > <p><a href="link2">label2</a></p>
> > <p>Text3 <a href="link3">label3</a> text4 <a
> > href="link4">label4</a> text 5</p>
> > </p>
>
> Well, your nesting of <p>'s within <p>'s is invalid HTML, so I'll take the
> liberty of changing the enclosing one to a <div>. These 3 templates should
> handle any arbitrary nesting of text, p, and link elements in the source
> tree.
>
> <xsl:template match="text">
> <div>
> <xsl:apply-templates/>
> </div>
> </xsl:template>
>
> <xsl:template match="p">
> <p>
> <xsl:apply-templates/>
> </p>
> </xsl:template>
>
> <xsl:template match="link">
Shouldn't this be <xsl:template match="a">? Not trying to look over your
shoulder, just clear up any confusion....
-Brett
> <a href="{@href}">
> <xsl:apply-templates/>
> </a>
> </xsl:template>
>
> To help understand why they work, remember there are built-in templates:
>
> <xsl:template match="*|/">
> <xsl:apply-templates/>
> </xsl:template>
>
> <xsl:template match="text()|@*">
> <xsl:value-of select="."/>
> </xsl:template>
>
> And know that <xsl:apply-templates/>, if no select attribute is given,
will
> find the templates that best match each child of the current node, and
will
> invoke them one by one.
>
>
> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
>
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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