Subject: RE: position() of the parent From: Kay Michael <Michael.Kay@xxxxxxx> Date: Thu, 20 Jan 2000 17:09:00 -0000 |
> Worked great! But just for my curiosity, is there any way to > find the position() of the parent? position() returns the position of the current node in the current node list. The parent of the current node is not generally a member of the current node list, therefore it does not have a position(). In fact, it is meaningless to talk of the position() of any node other than the current node. What you could determine is its <xsl:number>, which is not the same thing at all. Mike Kay XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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