Subject: RE: XML -> XSL -> same XML From: "Frederic FAURE" <frederic.faure@xxxxxxxxxxx> Date: Thu, 09 Mar 2000 17:33 +0100 |
This can be done with: <xsl:template match="/ | * | @* | text()"> <whatever/> <xsl:copy> <xsl:apply-templates select="*|@*|text()"/> </xsl:copy> <whatever/> </xsl:template> -----Message d'origine----- De: xsl-list@xxxxxxxxxxxxxxxx Date: jeudi 9 mars 2000 18:00 À: xsl-list@xxxxxxxxxxxxxxxx Objet: XML -> XSL -> same XML How do I transform an XML with an XSL that spits out the same XML document that was inputted, except with a particular heading or footer. Is there any way I can do this without re-specifying every XML tag in the XSL? XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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