RE: selecting a node without its children

["Selva, Francis" <Francis.Selva@xxxxxxxxxxxxxxx>]

Mike,
    This is not working for me.Why?.I have to use
     <xsl:template match="/">
        <xsl:for-each select="STORY">
	    <xsl:for-each select="AUTHOR">
            <xsl:value-of select="@id"/>
	    </xsl:for-each>
        </xsl:for-each>
     </xsl:template>
Where exactly the code u gave will work?.

Thanx,
Francis

> -----Original Message-----
> From: Kay Michael [mailto:Michael.Kay@xxxxxxx]
> Sent: Thursday, March 30, 2000 7:07 PM
> To: 'xsl-list@xxxxxxxxxxxxxxxx'
> Subject: RE: selecting a node without its children
> 
> 
> > This is my XML
> > 
> > 	<STORY>
> > 		<AUTHOR id="xsw">Stephen King</AUTHOR>
> > 	</STORY>
> > 
> > If I have a template
> > 
> > <xsl:template match="STORY">
> > 	....
> > </xsl:template>
> > 
> > how can i get the id attribute of author inside that template?
> 
> <xsl:value-of select="AUTHOR/@id"/>
> 
> Mike Kay
> 
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 


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