Subject: Sibling sort order From: Richard Bell <RichardBell@xxxxxxxxxxx> Date: Fri, 31 Mar 2000 14:17:05 +0100 |
Does anyone know how to select the previous/next sibling while maintaining the sort order of the current context using Microsoft's XSLT March preview? The only mechanism I can find to refer to the siblings of the context node is to use the parent axis (parent::) but any sort order which is being applied in the context of the current node is lost and the node order reverts to the order in the original document. Example below. Tks. <root> <row f1="f" f2="1"/> <row f1="e" f2="2"/> <row f1="d" f2="3"/> <row f1="c" f2="4"/> <row f1="b" f2="5"/> <row f1="a" f2="6"/> </root> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:template match="/"> <xsl:apply-templates select="*"> </xsl:apply-templates> </xsl:template> <xsl:template match="root"> <xsl:apply-templates select="*"> <xsl:sort select="@f1"/> </xsl:apply-templates> </xsl:template> <xsl:template match="row"> <div> <xsl:value-of select="@f1"/> <xsl:variable name="pos" select="position()-1"/> <xsl:value-of select="parent::*/*[position()=$pos]/attribute::f1"/> </div> </xsl:template> </xsl:stylesheet> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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