Re: xsl:if question

[David Carlisle <davidc@xxxxxxxxx>]

delete your { } they should generate a syntax error from your xpath
parser, although apparently don't on your system.

 test="/foo/bar != /foo/cow">  

is syntactically correct, but might not be what you want. Using != one
node sets almost never gives what anyone ever wants. I try to avoid
using != at all.  If there are more than one bar or crow element
then the above will be true if _any_ bar is not equal to _any_ cow.
compare with
 test="not(/foo/bar = /foo/cow)">  
which is true if there is no bar which is equal to cow

David


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