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Subject: RE: parameter setting From: Larry_Mason@xxxxxx Date: Wed, 19 Apr 2000 15:20:24 -0500 |
If the default value is 'output' how do you expect the value to be set to
'vanaja'? Is there something else that you haven't included in these
emails? I provide parameter values externally to my servlet which makes
calls to set the XSLT "variables". Something like the following
/servlet/myxslt?param1=vanaja&xmlfile=foo.xml&xslfile=bar.xsl
Not sure what calls are available in each of the XSLT processors, but it
works great in XT (and others I'm sure too) !!
Larry
"vanaja gogineni"
<vanaja_g@xxxxxxxxxxx To: xsl-list@xxxxxxxxxxxxxxxx
> cc:
Sent by: Subject: RE: parameter setting
owner-xsl-list@mulber
rytech.com
04/19/2000 03:04 PM
Please respond to
xsl-list
Thanku
I tried like that but still
I am unable to get it, I removed
select also it is not working .
is there any other way pl suggest me.
Thanks ®ards
vanaja
--
On Wed, 19 Apr 2000 09:10:22 Selva, Francis wrote:
>Well I guess the reason is you have the string 'output' as ur default
value
>which overwrites your actual parameter.If you remove the select
attribute,it
>will work.
>
>Francis
>
>
>> my xsl looks like this
>> ----------------------------------------------
>> it is a top level parameter
>>
>> <xsl:param name="param1" select="'output'"/>
>>
>> and I am using this variable in-between
>> like this
>>
>> <xsl:value-of select="$param1"/>
>>
>>
>> result is
>>
>> "output"
>>
>> but I want "vanaja" to be displayed
>>
>> what is the wrong with this
>>
>>
>> Thanks & regards
>>
>> Vanaja
>>
>
>
>
> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
>
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