Subject: Re:xsl:text output literal text From: Rhonda Fischer <rhonda@xxxxxxxxxxxxxx> Date: Mon, 05 Jun 2000 07:18:08 +0000 |
>Need to understand what you are trying to achieve! > >Mike Kay Howdy Mike, Thank you for your reply. I am attempting to perform xsl conditional statements to determine text that appears and variable substitution. Therefore I have put my entire source document in an xsl template matching on root (ProjectPlan). An example follows. The error message I receive is 'null'. definition.xml ----------- <?xml version='1.0' encoding='UTF-8' standalone='no'?> <!DOCTYPE ProjectPlan [ <!-- Here-in lies the DTD --> ]> <ProjectPlan> <Variable> <Entry name='Client.Fullname'>Special Client Pty Ltd</Entry> <Entry name='Date.DeliveryWeeks' value='12'/> </Variable> </ProjectPlan> master.xsl -------- <?xml version="1.0"?> <!DOCTYPE xsl:stylesheet> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="xml"/> <xsl:template match='/'> <Template> <Content> <Section> <SectionHeading>News</SectionHeading> <Section> <SectionHeading>News Details</SectionHeading> <xsl:if test='ProjectPlan/Variable/Entry[ @name="Date.DeliveryWeeks"]/@value > 10'> <para> A block of text </para> </xsl:if> <para> Our customer <xsl:copy-of select='ProjectPlan/Variable /Entry[@name="Client.Fullname"]/node()'/> some more text. </para> </Section> </Section> </Content> </Template> </xsl:template> command line: ----------- java com.icl.saxon.StyleSheet definition.xml master.xsl > newMaster.xml I then intend to continue to apply further xsl template matches on the newMaster.xml document to determine further formatting. Any suggestions is very much appreciated. Kind Regards Rhonda XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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