Subject: RE: ../name()? From: "Mathias Bonnard" <mathias.bonnard@xxxxxxxxxxx> Date: Fri, 23 Jun 2000 15:12:51 +0200 |
Jason, >Hi. Is there a better way to get the name of an node's parent then the >following? This works but seems awkward. > ><xsl:for-each select='..'><xsl:value-of select='name()'/></xsl:for-each> As name is an XPath function taking an optional nodeset argument, <xsl:value-of select='name(..)'/> should work. Hope this helps. Mathias Bonnard Euroclid mathias.bolnnard@xxxxxxxxxxx XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: ../name()?, Nikolai Grigoriev | Thread | xsl self-documentation on the fly (, John Greek |
Re: XLS files scrambling, Eric van der Vlist | Date | RE: XLS files scrambling, Matt Sergeant |
Month |