Re: a new(?) grouping problem

Subject: Re: a new(?) grouping problem
From: "Nikolai Grigoriev" <grig@xxxxxxxxxxx>
Date: Thu, 29 Jun 2000 19:34:21 +0400

> I want to group consecutive days with the same hours together, and just
> print the first and last day in each group.

The same solution as posted before, but slightly shorter ;-)

<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl=""; version="1.0">

<xsl:output method="html" version="4.0"/>

<!-- Root template: just create a table. -->
<xsl:template match="Hours">

<!-- Exclude holidays from processing -->
<xsl:template match="Holidays" priority="2"/>

<!-- Single days, except for holidays. -->
<!-- A modeless template creates the row -->
<xsl:template match="Hours/*">
  <xsl:variable name="hours" select="text()"/>
        <xsl:value-of select="name()"/>
        <xsl:apply-templates mode="end"

      <td><xsl:value-of select="."/></td>

<!-- A day closes the period if there's no better candidate -->
<xsl:template match="Hours/*" mode="end">
  <xsl:variable name="hours" select="text()"/>
      <xsl:apply-templates mode="end"
      <xsl:text> - </xsl:text><xsl:value-of select="name()"/>


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