to extract the longest string. (fwd)

["C.V. Radhakrishnan" <cvr@xxxxxxxxxxxxxxx>]

Jeni Tennison 

While sending the following code you said

<xsl:template match="row" mode="get-longest">
  <xsl:variable name="current">
    <xsl:for-each select="col">
      <xsl:value-of select="@align" />
    </xsl:for-each>
  </xsl:variable>
  <xsl:variable name="longest">
    <xsl:apply-templates select="following-sibling::row[1]"
                         mode="get-longest" />
  </xsl:variable>
  <xsl:choose>
    <xsl:when test="string-length($longest) > string-length($current)">
      <xsl:value-of select="$longest" />
    </xsl:when>
    <xsl:otherwise><xsl:value-of select="$current" /></xsl:otherwise>
  </xsl:choose>


  " So in effect calling this template on the second row
    element returns the longest result from all the rest of the rows," 

Would you please explain to me how calling this template on the second row
element returns the longest result from all  "the rest of rows" and how
the recursion is working in that place?

Thanks

Rajagopal




 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list