Re: Repeating something "n" times.

[Wendell Piez <wapiez@xxxxxxxxxxxxxxxx>]

I like recursion too, but it's true it can be ungainly. To get back to 
Robert's original question

> How do I repeat something 'n' times without a node list with n elements?

Take a node list with more than n elements and use [position() <= $n]....

<xsl:stylesheet version="1.0"
                xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

<xsl:variable name="elements" select="//*"/>

<xsl:param name="times" select="0"/>

<xsl:template match="/">
  <xsl:call-template name="breaks">
    <xsl:with-param name="times" select="$times"/>
  </xsl:call-template>
</xsl:template>

<xsl:template name="breaks">
  <xsl:param name="times" select="$times"/>
  <xsl:for-each select="$elements[position() &lt;= $times]">
    <br/>
  </xsl:for-each>
</xsl:template>

</xsl:stylesheet>

Note that in the real case you don't need the extra overhead of that 
top-level declaration for $times (this is just for testing).

Cheers,
Wendell

At 06:23 PM 11/6/00 -0700, Mike Brown wrote:
> [When XSLT 1.1 provides node-set casting] it will
> also be possible to create the equivalent of arrays and hashes.

That will be fun.


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Wendell Piez                            mailto:wapiez@xxxxxxxxxxxxxxxx
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