Subject: [xsl] Namespace question From: Ayelet Kotzer <akotzer@xxxxxxxxxxx> Date: Wed, 03 Jan 2001 16:21:59 -0800 |
Ayelet Kotzer wrote: > > (Desired) Output: > <A > > <A1>something </A1> > <A2 att="att1>something </A2> > </A> > > What I got is something like this: > <A1 xmlns:m="B">something </A1> > <A2 xmlns:m="B" att="att1 >something </A2> > Dimitre Novatchev wrote: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:m="B" exclude-result-prefixes="m" > Thanks. But - My problem is a little bit more complicate then what I described first. The xml root out file can be different. <xsl:template match="/"> <xsl:if test=".//E1"> <xsl:apply-templates select=".//E1"/> </xsl:if> <xsl:if test=".//E2"> <xsl:apply-templates select=".//E2"/> </xsl:if> </xsl:template> <xsl:template match="E1"> <xsl:element name="D1"> copy sourc elements </xsl:element> </xsl:template> <xsl:template match="E2"> <xsl:element name="D2"> copy sourc elements </xsl:element> </xsl:template> One output should be with the namespace and the other without : <D1 xmlns:m="B"> <A1>something </A1> <A2 att="att1>something </A2> </D1> <D2 > <A1>something </A1> <A2 att="att1>something </A2> </D2> Where I use xsl:copy the xmlns will be copy - which I am not interested in. If I write the exclude-result-prefixes="m" as part of the xsl:stylesheet then none of them will have the namespace. I tried to add the namespace to the root as attribute and fail. I have tried as namespace name and I didn't got what I expected wither. Your help will be more then welcome. Thanks, Ayelet XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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