Re: [xsl] multiple documents, namespaces and the same structure

[David Carlisle <davidc@xxxxxxxxx>]

Equivalent to what you said you had would be

<xsl:for-each 
  select="//*[local-name(.)='business']/*[local-name(.)='us.address']">

	<xsl:value-of select="."/>
	<xsl:value-of select="@address.type"/>
	<!-- see below <xsl:value-of select="*[local-name(.)='street']"/>-->
	<xsl:value-of select="street"/>

</xsl:for-each>

which would work for any namespace as long as the local names were as
given. 

but that would seem to produce a strange output.

Given
          <us.address address.type="street"> 
		<street>222 Kearney St.</street> 
		<street>Suite 500</street> 
		<city>San Francisco</city> 
		<state>CA</state><zip main="94108" sub="1234"/> 
	 </us.address> 

your template


<xsl:template name="format.address">
<xsl:param name="address.node"/>
	<xsl:value-of select="$address.node"/>
	<xsl:value-of select="$address.node/@address.type"/>
	<xsl:value-of select="$address.node/street"/>
</xsl:template>

surely produces

222 Kearney St.Suite 500San FranciscoCAstreet222 Kearney St.Suite 500
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
$address.node
                                       ^^^^^^
                                       $address.node/@address.type
                                             ^^^^^^^^^^^^^^^^^^^^^^^^^
                                             $address.node/street

As you can see, you can use local-name() to make a template apply to any
namespace, but if these address constructs mean the same thing in
different files why are they in different namespaces? It would be more
in the spirit of the game if you placed common elements in a common
namespace. 

Oh actually you don't get the street name twice, as 
<xsl:value-of select="$address.node/street"/>
presumably never selects anything as there isn't an element street in
the null namespace. it's always in the namespace attatched to (for
example) commercial: 

so your example produces

222 Kearney St.Suite 500San FranciscoCAstreet

no?


David

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