Re: [xsl] Newbie document() question

Subject: Re: [xsl] Newbie document() question
From: David Carlisle <davidc@xxxxxxxxx>
Date: Fri, 12 Jan 2001 16:52:44 GMT
> <xsl:variable name='otherDoc' select='document(MyXml.xml)'/>

MyXml.xml is a valid QName so will be evaluated to return all the
<myXML.xml> element nodes that are children of the root of
document a.

This is most likely empty, and anyway isn't what you want:-)

<xsl:variable name='otherDoc' select='document("MyXml.xml")'/>

is closer, but you don't really need a variable at all.

All you need do is copy the identity transformation from the XSL spec
and then add one extra template

<xsl:template match="some-xpath-that-matches-where-you-want-to-graft">
 <xsl:copy-of select='document('MyXml.xml')"/>


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