Subject: Re: [xsl] using xsl:copy From: Frank Hess <hess.frank@xxxxxx> Date: Tue, 23 Jan 2001 18:19:44 +0100 |
<xsl:template match="/catalog/item"> <xsl:apply-templates select="description"/> </xsl:template>
<xsl:template match="description"> <xsl:copy-of select="."/> </xsl:template>
If I have an xml structure like this:
<catalog> <item> <description><b>A nice shoe</b></description> </item> </catalog>
and my xsl looks like this:
<xsl:template match="/catalog/item"> <xsl:copy-of select="description"/> </xsl:template>
my HTML output is: <description><b>A nice shoe</b></description>
How can I output the html without the <description> tags? I wish to preserve the <b> tags which may or may not be there.
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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