[xsl] xsl, position, template Problem

Subject: [xsl] xsl, position, template Problem
From: "Partho Paul" <uk4u@xxxxxxxxxxxxxxxxxxx>
Date: Wed, 31 Jan 2001 11:51:46 +0100
I have the following xml given:

Some useful Text
<Stretchext>Bla Bla - some usefule thing</Stretchext>
Another useful text
<Stretchext>Bla Bla - some usefule thing</Stretchext>
Further useful text

The Probelm is, how to create a xsl Stylesheet?

I used the following:
<xsl:template match="Para">
<xsl:apply-templates select="//Stretchtext"/>

<xsl:template match="Stretchtext"/>
<xsl:value-of select="position()"/>

The problem now is that the function postion() works well, but
I don't get the output of the text from the xml File.
If I do the following:

<xsl:template match="Para">
<xsl:apply-templates />

I do get the output of the texts, but now the function position()
dos not count correctly.

So how can I get the output of the text according to its occurance
and count the Stretchtext-Tags correctly.

Thank you.


Partho Paul                     email: uk4u@xxxxxxxxxxxxxxxxxxx
Computer science student        or:    paul@xxxxxxxxx
Homepage:   http://www.partho.de
Durga Puja: http://www.uni-karlsruhe.de/~uk4u/durga.html

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