Subject: Re: [xsl] Q: Passing constructed elements as parameters From: David Carlisle <davidc@xxxxxxxxx> Date: Wed, 31 Jan 2001 19:27:04 GMT |
Hi, I'm trying to do something like: <xsl:apply-template> <xsl:with-param name="foo"> <xsl:element name="bar"> ... </xsl:element> </xsl:with-param> </xsl:apply-template> <xsl:template> assuming you mean <xsl:template match="xxx"> here <xsl:param name="foo"/> <xsl:for-each select="$foo/bar"/> </xsl:template> But something seems to be lost in the translation. Is there some conversion step I'm missing? --George if the xxx element that matches the second template is a direct child of the template that has the apply-templates code at the top then it will see the seting of the foo parameter. (otherwise it won't as parameters are not passed on by default) However if you go <xsl:with-param name="foo"> .... </xsl:with-param> rather than <xsl:with-param name="foo" select="..."/> then $foo wilkl be a result tree fragment rather than a node set, so you can not query into it with <xsl:for-each select="$foo/bar"/> It's not clear from what you've posted whether you want to use th e <xsl:with-param name="foo" select="..."/> for and have $ foo being a set of nodes in the input document, or whether you did intent to construct a new node set, in which case you processor may have a node-set() extension function, used as <xsl:for-each select="xt:node-set($foo)/bar"/> David XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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