Re: [xsl] merging two documents - only if second document matches

[Oliver Becker <obecker@xxxxxxxxxxxxxxxxxxxxxxx>]

Hi Matt,

> I have two documents, file A and file B.  I want to join them on the id of
> the first, but only if a matching id is in the 2nd.  How do I do this?
> 
> File A              File B               Desired Output
> <id> A </id>        <id> A </id>         <id> A </id>
> <id> B </id>        <id> C </id>         <id> D </id>
> <id> D </id>        <id> D </id>

This looks like the intersection of the elements of the two files.
Assuming there is a root element <ids> in each file, these are
named fileA.xml and fileB.xml respectively, the following lines
produce the desired output:

<xsl:variable name="idsA" select="document('fileA.xml')/ids/id" />
<xsl:variable name="idsB" select="document('fileB.xml')/ids/id" />

<xsl:template match="/">
   <xsl:for-each select="$idsA[. = $idsB]">
      <xsl:copy-of select="." />
   </xsl:for-each>
</xsl:template>

The question is, if your input is really as simple as you said.
For example it might be reasonable comparing the normalized string
values like this
   normalize-space() = normalize-space($idsB)
inside of the predicate.

Hope that helps,
Oliver


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