Re: [xsl] Node set

Subject: Re: [xsl] Node set
From: YueMa <may@xxxxxxxxxxxxxxxx>
Date: Mon, 05 Feb 2001 15:49:11 -0500
Thanks for the solution, Jeni!
The reason I asked about ordered node set was that I have to group those
title elements in the sample XML...
(Now I'm clearly understand thata node set is not ordered.... ;-))
Say I may have 8 or 10 title elements and finally, I'm going to display
them within an HTML table, 4 on the left
and 4 on the right column....without specific ordering, it's easy.
And the bad news is the rule used to grouping them is "logic", so looks
like nothing I can follow.... and as I
said, the total number of title element is not guaranteed, if 4th element
was missing, I have to move the 5th
element to the left column!  ;(
Right now I just can not find a solution  for that, maybe this case is not
good for XSL, I think I'm going to write
a program to handle that......


Jeni Tennison wrote:

> Hi YueMa,
> > How can I create a node set with specific order other than document
> > order?
> As David "pure mathematician" Carlisle says, node sets aren't ordered,
> so you can't create one with an order, but you can choose what order
> to process them in.
> > How about if I want to  display like:
> > title2
> > title4
> > title1
> > title3
> Then apply templates (or use xsl:for-each) in that order:
>   <xsl:apply-templates select="title2" />
>   <xsl:apply-templates select="title4" />
>   <xsl:apply-templates select="title1" />
>   <xsl:apply-templates select="title3" />
> This hardcodes into the stylesheet the order in which they're
> processed in a certain context.  You could select the order in any
> number of ways.
> > the order is not fixed and may changd everytime, and even the number
> > of titles are not guaranteed, maybe 4, maybe 3, etc.
> There must be some underlying way of choosing which order you want
> them in?  What is it?
> > What I wanted to do is to create a node set with the particular
> > order and then I can process elements just by using <xsl:for-each>,
> > is that possible in XSL?
> Not really (although you could feasibly create a result tree fragment
> variable and then iterate over that with xsl:for-each having turned it
> into a node set with an extension function).
> If you apply templates to the nodes you want in order, as outlined
> above, then you can have a template that matches any of them and that
> contains whatever you want to put in the body of the xsl:for-each:
> <xsl:template match="title1 | title2 | title3 | title4">
>    ... body of the xsl:for-each ...
> </xsl:template>
> I hope that helps,
> Jeni
> ---
> Jeni Tennison
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