Subject: [xsl] Getting the current document URL from within XSLT From: Mike Moran <Mike.Moran@xxxxxxxxxxx> Date: Tue, 06 Feb 2001 17:37:49 +0000 |
Is this possible? I haven't got any refs to hand right now, but I've done a quick search of my XSL List folder and the web, to no avail. Why do I want to do this? Well, I am using axkit[1] to produce `simple' and `complex' versions of a document (which is simple XHTML to start with). I want to include a link in each version which points to the other, so that a user can move between the different versions if they so wish. Axkit allows you to specify the style by looking for "?style=foo" at the end of the URL eg: "http://foo.com/doc.xml?style=foo". I want to embed a link in the output produced from the "doc.xml" document without having to specify the "doc.xml" or "http://foo.com/doc.xml" as part of the data the stylesheet reads, so: "http://foo.com/doc.xml?style=simple" contains: ... <a href="http://foo.com/doc.xml?style=complex">Complex version</a> and "http://foo.com/doc.xml?style=complex" contains: ... <a href="http://foo.com/doc.xml?style=simple">Simple version</a> Is this possible, perhaps through extensions? I am currently using Sablotron[2] via Axkit[1]. [1]: www.axkit.org [2]: www.gingerall.com -- Mike.Moran@xxxxxxxxxxx Web: http://houseofmoran.com/ AvantGo: http://houseofmoran.com/Lite/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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