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Subject: [xsl] position of nodes From: "Partho Paul" <uk4u@xxxxxxxxxxxxxxxxxxx> Date: Sat, 10 Feb 2001 12:52:40 +0100 |
Following problem: numbering nodes
I have the following xml-structure:
Chapter
/ \
/ \
/ \
Paragraph Paragraph
/ | \ \ / | \ \
/ | \ \ / | \ \
/ | \ \ / | \ \
/ | \ \ / | \ \
Text StretchText Text StretchText Text StretchText Text StretchText
1 2 3 4
What already works for the upper tree is with
<xsl:template match="StretchText">
<xsl:number level="any" />
</xsl:template>
or
<xsl:value-of select="count(preceding::StretchText) + 1"/>
Now I want to number the StretchText from the Paragraph node, which will look
like beneath:
Chapter
/ \
/ \
/ \
Paragraph Paragraph
/ | \ \ / | \ \
/ | \ \ / | \ \
/ | \ \ / | \ \
/ | \ \ / | \ \
Text StretchText Text StretchText Text StretchText Text StretchText
1 2 1 2
How can that be done? Tried some modification of the above xsl, but nothing worked so far.
Thanx in advance!
_______________________________________________________________________
Partho Paul email: uk4u@xxxxxxxxxxxxxxxxxxx
Computer science student or: paul@xxxxxxxxx
-----------------------------------------------------------------------
Homepage: http://www.partho.de
Durga Puja: http://www.uni-karlsruhe.de/~uk4u/durga.html
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