Subject: [xsl] Re: testing for child nodes From: Dimitre Novatchev <dnovatchev@xxxxxxxxx> Date: Sat, 24 Feb 2001 10:40:51 -0800 (PST) |
Robert Koberg wrote: > I display the test value like so: > **<xsl:value-of select="not(child::node())"/>** > for a node that looks like this: > <pointer role="News1" fileref="news1.xml"/> > > but the result is always true. How do you test for this? The pertinent part > of the XSL is below: > > <xsl:choose> > <xsl:when test="node()!=text() and not(child::node())"> > ................................. What is always false in your case is: node()!=text() This will be true if the current node has both text and non-text child nodes. As your current node does not have any node() children at all, the above is false and the whole "and"-expression: node()!=text() and not(child::node()) is also false. Most probably you wanted to specify the following: <xsl:when test="not(self::text()) and not(child::node())"> This makes more sense, but will also be true for comments and PI-s For an element that has no children (elements, comments, PIs, text), specify the following expression: not(node()) Dimitre Novatchev. __________________________________________________ Do You Yahoo!? Get email at your own domain with Yahoo! Mail. http://personal.mail.yahoo.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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