Antwort: [xsl] copying source tree

Subject: Antwort: [xsl] copying source tree
From: "Ulrich Becker" <ulrich.becker@xxxxxx>
Date: Wed, 14 Mar 2001 16:50:02 +0100

You aren't copying anything without xsl:copy or xsl:copy-of.


<xsl:template match="node()|@*">
   <xsl:copy>
     <xsl:apply-templates select="node()|@*"/>
   </xsl:copy>
 </xsl:template>

and i think you want :
<xsl:template match="/">
        <xsl:apply-templates/>
</xsl:template>
(It will work without also.)

Bye
Uli
 (Sorry, if I'm writing silly stuff. I'm only a newbie too and i use easy questions as exercises.)

Shouldn't the following copy source to the result tree?

<xsl:template match="@*|node()" >
   <xsl:apply-templates
    select = "@*|node()"/>
</xsl:template>
<xsl:template match="/">
        <xsl:apply-templates select="*" />
</xsl:template>

I want to make changes only to a node in the
source tree by matching in the second template.
This one does not seem to copy the source tree.
_________________________________________________________________




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