Re: [xsl] Absolute position

Subject: Re: [xsl] Absolute position
From: Paul Grosso <pgrosso@xxxxxxxxxxxxx>
Date: Thu, 15 Mar 2001 17:11:32 -0600
Does <xsl:number level="any" count="*"/> give what you want?

At 04:23 2001 03 15 -0500, Carmelo Montanez wrote:
>    Does anyone knows how to get the aboslute value of an element
>within a tree? and by that I  mean the order on which it is listed
>within that tree.  Look at the tree below
>
>  <child1>
>  </child1>
>  <child2>
>     <child2-1>
>          <child2-1-1>
>             <child2-1-1-1>
>             </child2-1-1-1>
>          </child2-1-1>
>     </child2-1>
>  </child2>
>  <child3>
>      <child3-1>
>      </child3-1>
>  </child3>
>  <child4>
>  </child4>
></parent>
>
>To be more clear I am looking for this type of information
>
>"child1" - is number 1
>"child2" - is number 2
>"child2-1" - is number 3
>"child2-1-1" is number 4
>"child2-1-1-1" is number 5
>"child3" is number 6
>"child3-1" is number 7
>"child4" is number 8
>
>and so on ....
>
>in other words its "absolute position" as you read from to to bottom and
>I want to know that information when THAT node is the context node
>in other words if  "child6" is the current node I want to know that
>it is really number 6 as I read. Any ideas?


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