Subject: Re: [xsl] Absolute position From: Paul Grosso <pgrosso@xxxxxxxxxxxxx> Date: Thu, 15 Mar 2001 17:11:32 -0600 |
Does <xsl:number level="any" count="*"/> give what you want? At 04:23 2001 03 15 -0500, Carmelo Montanez wrote: > Does anyone knows how to get the aboslute value of an element >within a tree? and by that I mean the order on which it is listed >within that tree. Look at the tree below > > <child1> > </child1> > <child2> > <child2-1> > <child2-1-1> > <child2-1-1-1> > </child2-1-1-1> > </child2-1-1> > </child2-1> > </child2> > <child3> > <child3-1> > </child3-1> > </child3> > <child4> > </child4> ></parent> > >To be more clear I am looking for this type of information > >"child1" - is number 1 >"child2" - is number 2 >"child2-1" - is number 3 >"child2-1-1" is number 4 >"child2-1-1-1" is number 5 >"child3" is number 6 >"child3-1" is number 7 >"child4" is number 8 > >and so on .... > >in other words its "absolute position" as you read from to to bottom and >I want to know that information when THAT node is the context node >in other words if "child6" is the current node I want to know that >it is really number 6 as I read. Any ideas? XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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