[xsl] Re: Absolute position

[Dimitre Novatchev <dnovatchev@xxxxxxxxx>]

count(
(preceding::node()|ancestor::node())
       [count(. | $p/descendant::node()) = count($p/descendant::node()) ]
)


where $p contains some single ancesstor of the current node.

Carmelo Montanez wrote
Thanks Wendell ......

Almost there ..... however, I want to constraint the selection a bit more,
look
at a more descriptive tree.  I want to select the position within each
"parent"
subtree.  In other words "child3" is number 5 within the first "parent"
subtree
but it will be number 6 at the second "parent" subtree.


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