RE: [xsl] Ignoring Child Nodes using XPath

["Ciaran Byrne" <ciaran.byrne@xxxxxxx>]

Sorry,
	I should have mentioned the fact that I'm not using the
XPath Query in an XSL stylesheet but rather to select the
node in MSXML i.e. dom.selectsinglenode("XPath Query").

I know I could concat the element together by getting the element
name and attributes but I thought there might have been a
more efficient solution using an XPath Query.

-----Original Message-----
From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
[mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Michael Kay
Sent: Monday, March 26, 2001 1:58 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: RE: [xsl] Ignoring Child Nodes using XPath


> 	Is there a way in which I can
> select a node ignoring the child nodes
> as in the following example:
>
> What I have...
>
> <p align="left">
> Here <b>is</b> some content<br/>
> </p>
>
> What I want...
> <p alignt="left"></p>

There are many ways of ignoring the child nodes, in fact they will always be
ignored unless you specifically do something to access them.

Try
<xsl:template match="p">
  <xsl:copy/>
  <xsl:copy-of select="@*"/>
</xsl:template>

Mike Kay
Software AG


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