Subject: [xsl] replace each same character by another one (or more) From: Kristof Bernaert <kbernaert@xxxxxxxxxxx> Date: Tue, 27 Mar 2001 11:29:16 +0200 |
where a quote-sign ( ' ) is used in xml-doc, it has to be replaced by slash + quote-sign ( /' ) how to process a whole document at once ? i tried already like this: <xsl:template match="Body"><xsl:value-of select=" .... but this don't result in a node, just the value of, with the result when the element Body is called, only the value is given, thus, without the lay-out defined in 'template-match' for elements included in the Body element ps: the only way i can call the node Body is like this, <xsl:apply-templates select="Information/Body"/> (within javascript) some nice brain with solution ? :-) thx XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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