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Subject: [xsl] I can't transform XML in code... From: "Poh Justin KT" <nitsujpoh@xxxxxxxxxxx> Date: Fri, 27 Apr 2001 16:17:47 +0800 |
import org.apache.xalan.xslt.XSLTProcessor; import org.apache.xalan.xslt.XSLTResultTarget; import org.apache.xalan.xslt.XSLTInputSource; import org.apache.xalan.xslt.XSLTProcessorFactory; import com.lotus.xsl.*; import org.xml.sax.SAXException; import java.io.*; import org.xml.sax.*;
public class test30
{
public static void main(String[] args)
{
try
{
XSLTInputSource inputXML = new XSLTInputSource("trying1.xml");
XSLTInputSource inputXSL = new XSLTInputSource("trying.xsl");
XSLTProcessor processor = XSLTProcessorFactory.getProcessor();
processor.process(inputXML, inputXSL, new XSLTResultTarget(System.out));
}catch(Exception e)
{
System.out.println(e);
}
}
}_________________________________________________________________________ Get Your Private, Free E-mail from MSN Hotmail at http://www.hotmail.com.
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