Subject: Re: [xsl] Accessing nth element From: Bharat.Chintapally@xxxxxxxxxxxxxxxxx Date: Tue, 1 May 2001 09:30:42 -0400 |
I am sorry correction: I am not using for-each but I am using templates. Should I switch to for-each with a selection to achieve what I am doing.. Thanks --bharat --------------------------------------------------------------- Bharat Chintapally CommerceQuest Inc. bharat.chintapally@xxxxxxxxxxxxxxxxx New Phone # 813-639-6478 --------------------------------------------------------------- Janning Vygen <vygen@xxxxxxxxxxxx> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx, Sent by: Bharat.Chintapally@xxxxxxxxxxxxxxxxx owner-xsl-list@xxxxxxxxxxxx cc: rytech.com Subject: Re: [xsl] Accessing nth element 05/01/01 09:23 AM Please respond to xsl-list Am Dienstag, 1. Mai 2001 15:04 schrieb Bharat.Chintapally@xxxxxxxxxxxxxxxxx: > Hello all: > I think I need to replace for-each in my XSLT's with recursion. I am > interested in picking 'x' elements from 'y' (20 for each page from 500 > records) for paging. for-each is working fine, but it is overkill, I should > be able to terminate (return from as in procedural lang's) processing when > I finish processing 20 records for a given page. > I am trying to switch to recursion, but have a quick question. Is > there a way to fetch an n'th element from given bunch of records. For > example when I am processing records 20 thru records 40 out of 500 records, > I would like directly fetch the record #20 from all the records. Is it > possible.. try something like this <xsl:for-each select="./records[position() < 20]"> not tested, but with position function inside your XPath expression you should get the records you want. janning -- Planwerk 6 /websolutions Herzogstraße 86 40215 Düsseldorf fon 0211-6015919 fax 0211-6015917 http://www.planwerk6.de XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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