Subject: Re: [xsl] question about position() From: Oliver Becker <obecker@xxxxxxxxxxxxxxxxxxxxxxx> Date: Thu, 17 May 2001 16:16:52 +0200 (MET DST) |
> first xsl example: > <xsl:stylesheet version="1.0" > xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> > > <xsl:template match="/"> > <xsl:apply-templates select="r/a"> > <xsl:sort data-type="number" select="@at"/> > <xsl:with-param name="p" select="position()"/> > </xsl:apply-templates> > </xsl:template> > > <xsl:template match="a"> > <xsl:param name="p"/> > <xsl:value-of select="$p"/><xsl:text>,</xsl:text> > </xsl:template> > > </xsl:stylesheet> > > output from first example: > -1,-1,-1,-1, In addition to Jeni's mail it is worth to remark that this output mustn't appear at all. position() should never return -1. The correct output is 1 I think, so it must be a bug in the XSLT processor you're using. Cheers, Oliver /-------------------------------------------------------------------\ | ob|do Dipl.Inf. Oliver Becker | | --+-- E-Mail: obecker@xxxxxxxxxxxxxxxxxxxxxxx | | op|qo WWW: http://www.informatik.hu-berlin.de/~obecker | \-------------------------------------------------------------------/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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