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Subject: [xsl] How to parse a fragment result tree in the context of input tree From: Janning Vygen <vygen@xxxxxxxxxxxx> Date: Thu, 31 May 2001 17:20:24 +0200 |
Hi
first time i didnt get any answer, so i try again and explain my problem
again with a short example:
the key problem is, that i can apply stylesheet to a fragment tree which is
created in a template, but this fragment tree doesnt know where it belongs in
the source tree.
the second template generates a authorlist but can not include the proper
class. How can you apply templates to a result tree fragment and still have
access to the whole document??
i hope i get some suggestion this time. but maybe i just cant properly
explain my problem.
thanks in advance
janning
example.xsl:
<xsl:template match="authors">
<xsl:variable name="authorlist">
<itemizedlist>
<xsl:for-each select="author">
<listitem><xsl:value-of select="."/></listitem>
</xsl:for-each>
</itemizedlist>
</xsl:variable>
<xsl:apply-templates select="$authorlist"/>
</xsl:template>
<xsl:template match="itemizedlist">
<ul>
<xsl:attribute name="class">
<xsl:value-of select="ancestor-or-self::chapter/@id"/>
</xsl:attribute>
<xsl:apply-templates/>
</ul>
</xsl:template>
example.xml:
<book>
<chapter id="first">
<docinfo>
<authors>
<author>me</author>
<author>myself</author>
<author>and i</author>
</authors>
</docinfo>
<itemizedlist>
<listitem>normal</listitem>
<listitem>list</listitem>
<listitem>with items</listitem>
<itemizedlist>
</chapter>
<chapter id="second">
<itemizedlist>
<listitem>another</listitem>
<listitem>list</listitem>
<listitem>with items</listitem>
<itemizedlist>
</chapter>
</book>
html-result should be something like this:
<html>
<body>
<h1>chapter first</h1>
written by
<ul class="first">
<li>me</li>
<li>myself</li>
<li>and i</li>
</ul>
<ul class="first">
<li>normal</li>
<li>list</li>
<li>with items</li>
</ul>
<h1>chapter second</h1>
<ul class="first">
<li>normal</li>
<li>list</li>
<li>with items</li>
</ul>
</body>
</html>
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