Re: [xsl] Why is my xsl:param empty? (passed with xsl_with-param)

[Francis Norton <francis@xxxxxxxxxxx>]

Rene de Vries wrote:
> 
>         <xsl:template match="/">
> 
your xml-param is empty because the document root comes above the root
element. So when you apply-templates from the template with match="/",
the next thing that happens is that XSLT matches your element "root"
with the built-in template, then does an implicit apply-templates -
*without* repeating your with-param - and then matches the x element.

So all you need to do to get your template working is replace 

         <xsl:template match="/">

with

         <xsl:template match="root">

Hope this helps -

Francis.

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