Subject: Re: [xsl] Why is my xsl:param empty? (passed with xsl_with-param) From: Francis Norton <francis@xxxxxxxxxxx> Date: Fri, 15 Jun 2001 10:58:57 +0100 |
Rene de Vries wrote: > > <xsl:template match="/"> > your xml-param is empty because the document root comes above the root element. So when you apply-templates from the template with match="/", the next thing that happens is that XSLT matches your element "root" with the built-in template, then does an implicit apply-templates - *without* repeating your with-param - and then matches the x element. So all you need to do to get your template working is replace <xsl:template match="/"> with <xsl:template match="root"> Hope this helps - Francis. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] Why is my xsl:param empty, Conor Ryan | Thread | RE: [xsl] Why is my xsl:param empty, Rene de Vries |
RE: [xsl] Why is my xsl:param empty, Rene de Vries | Date | RE: [xsl] Why is my xsl:param empty, Michael Kay |
Month |