Re: [xsl] Getting equivalence classes on attributes

Subject: Re: [xsl] Getting equivalence classes on attributes
From: "Christopher R. Maden" <crism@xxxxxxxxx>
Date: Mon, 18 Jun 2001 00:38:00 -0700
At 21:15 17-06-2001, Rafael R. Sevilla wrote:
Hello.  Is there a way to write an XPath expression that will return each
equivalence class on the value of an attribute, i.e. every collection of
nodes whose value for a certain attribute are the same e.g.

<foo att="bar"/>

<foo att="bar" att2="quux"/>

<blah att="bar"/>

<foo att="baz"/>

<foo att="quux"/>

The first three elements would belong to one equivalence class on the
attribute 'att', while the fourth would belong to another, and the fifth
to yet another.  I would want an XPath expression that would return each
of these equivalence classes.  Is this possible?

Well, if you were going to match templates on bar, baz, or quux elements, you'd do this:

<xsl:template match="bar">

So if you want to match on all elements with an att attribute equal to "bar", try this:

<xsl:template match="*[@att='bar']">

If you want to find all such elements, you'd use an expression like "//*[@att='bar']".

Christopher R. Maden, XML Consultant
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