[xsl] Re: XSLT Problem

[Dimitre Novatchev <dnovatchev@xxxxxxxxx>]

Hi Alex,

> I've got result table where I can not color every other row because as I
> understand the system :
> 1. retrieves rows and sorts them by appropriate keys;
>    for example :
>      1-st row   (value of C-field is '  ') - black;
>      2-nd row (value of C-field is '11') - gray;
>      3-rd row  (value of C-field is '  ') - black;
>      4-th row   (value of C-field is '22') - gray;
>      5-th row   (value of C-field is '  ') - black;
>      6-th row   (value of C-field is '  ') - gray;
> 
> 2. and only then excludes 2-nd and 4-th rows( where field-C not = '  ')
> 
> So instead of sequence :
> 
> 1-st row (value of C-field is '  ') - black;
> 3-rd row (value of C-field is '  ') - gray;
> 5-th row (value of C-field is '  ') - black;
> 6-th row (value of C-field is '  ') - gray
> 
> I've got :
> 
> 1-st row (value of C-field is '  ') - black;
> 3-rd row (value of C-field is '  ') - black;
> 5-th row (value of C-field is '  ') - black;
> 6-th row (value of C-field is '  ') - gray
> 
> Or other words does XSLT give us the posibility to use something like "where" in
>  DB2 ?
> And if it does - how to use it within <xsl:for-each> or <xsl:apply-templates
> select="..."> BEFORE SORTING ?

Yes, there is such possibility -- a "predicate" can be placed at the end of every
location step.

In your case you'll have:


  <xsl:for-each select="Record01[field-C = '  ']">
      <!-- All contents as in your code, but remove the xsl:if -->
  </xsl:for-each>

Hope this helped,

Cheers,
Dimitre Novatchev.



Alex Genis wrote:

Hi ! Could you please help ?
My task is : to create HTML report from XML document and to color every other
row  for the result HTML table.
Everything is already done but I still have one problem:

If I use

  <xsl:for-each select="Record01">
   <xsl:sort select="field-A"/>
   <xsl:sort select="field-B"/>

     <xsl:if test="field-C = '  '" >
        <TR>
          <xsl:choose>
           <xsl:when test="position() mod 2 = 0">
             <TD   ...   class="C1">
                                       <xsl:value-of select="field-A"/>
             </TD>
             <TD   ...   class="C1">
                                       <xsl:value-of select="field-B"/>
             </TD>
             <TD   ...   class="C1">
                                       <xsl:value-of select="field-C"/>
             </TD>
           </xsl:when>
           <xsl:otherwise>
             <TD   ...   class="C2">
                                       <xsl:value-of select="field-A"/>
             </TD>
             <TD   ...   class="C2">
                                       <xsl:value-of select="field-B"/>
             </TD>
             <TD   ...   class="C2">
                                       <xsl:value-of select="field-C"/>
             </TD>
           </xsl:otherwise>
        </xsl:choose>
      </TR>
   </xsl:if>

</xsl:for-each>

I've got result table where I can not color every other row because as I
understand the system :
1. retrieves rows and sorts them by appropriate keys;
   for example :
     1-st row   (value of C-field is '  ') - black;
     2-nd row (value of C-field is '11') - gray;
     3-rd row  (value of C-field is '  ') - black;
     4-th row   (value of C-field is '22') - gray;
     5-th row   (value of C-field is '  ') - black;
     6-th row   (value of C-field is '  ') - gray;

2. and only then excludes 2-nd and 4-th rows( where field-C not = '  ')

So instead of sequence :

1-st row (value of C-field is '  ') - black;
3-rd row (value of C-field is '  ') - gray;
5-th row (value of C-field is '  ') - black;
6-th row (value of C-field is '  ') - gray

I've got :

1-st row (value of C-field is '  ') - black;
3-rd row (value of C-field is '  ') - black;
5-th row (value of C-field is '  ') - black;
6-th row (value of C-field is '  ') - gray

Or other words does XSLT give us the posibility to use something like "where" in
 DB2 ?
And if it does - how to use it within <xsl:for-each> or <xsl:apply-templates
select="..."> BEFORE SORTING ?

How this problem can be solved ?
Thanks a lot. Alex Genis.














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