Re: [xsl] Was test for presence of an attribute

[Goetz Bock <bock@xxxxxxxxxxx>]

On Fri, Jul 20 '01 at 12:39, val iliescu wrote:
> How would one go about to print the element names,
> followed imediately by their attribute name (if it
> exists ?)
That's easy: write a template that cataches all nodes (except text
nodes) and prints their (local) name, than does a for-each loop over all
attributes and print's this names. (And get yourselfe a good book)

It goes something along this lines (it produces recoverable errros with
saxon for the text nodes):


<?xml version="1.0" encoding="UTF-8" standalone="no" ?>
<!-- filename:      test.xsl 
     created on:    2001 Jul 21 20:48:16 z (CEST)
     last modified: 2001 Jul 21 21:00:23 z (CEST)
     (c) 2001 by Goetz Bock <bock@xxxxxxxxxxx>
     -->
<xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
               version='1.0'>
<xsl:output method="text" />

<xsl:template match="/">
  <xsl:apply-templates />
</xsl:template>

<xsl:template match="node()">
  <xsl:value-of select="name()" />
  <xsl:text>: </xsl:text>
  <xsl:for-each select="@*">
    <xsl:value-of select="name()" />
  </xsl:for-each>  
  <xsl:text>
</xsl:text>
  <xsl:apply-templates />
</xsl:template>
  
<xsl:template match="text()" />
</xsl:transform>


--   
Goetz Bock                                              IT Consultant
Dipl.-Inf. Univ.

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