Subject: [xsl] At xsl:choose, the value of "" is not a node-set From: Xiaocun Xu <xiaocunxu@xxxxxxxxx> Date: Wed, 1 Aug 2001 14:30:17 -0700 (PDT) |
Hi, I am puzzled at an error I am encountering: Transform failed: At xsl:choose on line 149 of file:/C:/test/gXML2ePASS_base.xsl: The value of "" is not a node-set The xsl:choose line in question is the one in the following code, line 4 in FixAttribute template. <xsl:template name="FixAttribute"> <xsl:param name="header"></xsl:param> <xsl:if test="./node()"> <xsl:choose> <xsl:when test="starts-with($header/cell[@column=current()/@column], '*')"> <xsl:attribute name="{substring($header/cell[@column=current()/@column], 2)}"> <xsl:call-template name="CheckForDate"> <xsl:with-param name="attributeName" select="$header/cell[@column=current()/@column]"/> </xsl:call-template> </xsl:attribute> </xsl:when> <xsl:otherwise> <xsl:attribute name="{$header/cell[@column=current()/@column]}"> <xsl:call-template name="CheckForDate"> <xsl:with-param name="attributeName" select="$header/cell[@column=current()/@column]"/> </xsl:call-template> </xsl:attribute> </xsl:otherwise> </xsl:choose> </xsl:if> </xsl:template> This template is called in: <xsl:template match="cell" mode="Organization"> <xsl:if test="current()"> <xsl:call-template name="FixAttribute"> <xsl:with-param name="header" select="$OrganizationHeader"/> </xsl:call-template> </xsl:if> </xsl:template> The "" node-set the error refers to is the cell element? If so, I should have filtered it out with <xsl:if test="./node()">, right? Any help would be very much appeciated. Xiaocun __________________________________________________ Do You Yahoo!? Make international calls for as low as $.04/minute with Yahoo! Messenger http://phonecard.yahoo.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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