Re: [xsl] Muenchian Method

[Jeni Tennison <mail@xxxxxxxxxxxxxxxx>]

Hi Doug,

> I would like to group an XML file so the HTML would be like this:

Your XSLT is almost there. The only problem is that the path you're
using in the use attribute of xsl:key (and later, when you try to get
unique nodes) isn't correct. Your key is:

<xsl:key name="contacts-by-surname" match="member" use="last_name" />

But you the last_name element isn't a direct child of the member
element - you should be stepping down through the name element, i.e.:

<xsl:key name="contacts-by-surname" match="member"
         use="name/last_name" />
              ^^^^^

Similarly, when you select the unique members, you need to use a path
that takes you from the member element to the last_name element, i.e.:

  member[count(.|key('contacts-by-surname', name/last_name)[1]) = 1]
                                            ^^^^^

In the final use of the key, you got the path right, but added quotes
around it, so it's trying to find members with the surname
"name/last_name", which I doubt anyone has. There, again, you need:

  key('contacts-by-surname', name/last_name)

I hope that helps,

Jeni

---
Jeni Tennison
http://www.jenitennison.com/


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list